2x^2-3.798x-4.3914=0

Solution for 2x^2-3.798x-4.3914=0 equation:

2x^2-3.798x-4.3914=0

a = 2; b = -3.798; c = -4.3914;
Δ = b2-4ac
Δ = -3.7982-4·2·(-4.3914)
Δ = 49.556004
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3.798)-\sqrt{49.556004}}{2*2}=\frac{3.798-\sqrt{49.556004}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3.798)+\sqrt{49.556004}}{2*2}=\frac{3.798+\sqrt{49.556004}}{4}
$